Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 206: 42a

Answer

$$ W=5.6 \times 10^{2} \mathrm{J} $$

Work Step by Step

The work done on the block by the worker is, using Eq. $7-7,$ $$ W=F d \cos \theta=[ 71 \mathrm{N} ]\ \ [ 9.2 \mathrm{m}]\ \mathrm{cos} 32^{\circ}=5.6 \times 10^{2} \mathrm{J} $$
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