Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 6 - Force and Motion-II - Problems - Page 147: 86a

Answer

The breaking will occur at the lowest point of the circle.

Work Step by Step

We can write an expression for the force on the stone from the cord at the top of the circle: $F+mg = \frac{mv^2}{r}$ $F = \frac{mv^2}{r} - mg$ We can write an expression for the force on the stone from the cord at the bottom of the circle: $F-mg = \frac{mv^2}{r}$ $F = \frac{mv^2}{r} + mg$ Since the required force is greater at the bottom of the circle, the breaking will occur at the lowest point of the circle.
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