Answer
$$9.1 \times 10^{-7} \mathrm{m}$$
Work Step by Step
The distance moved is $$r=v_{p} \Delta t=\left(9.1 \times 10^{5} \mathrm{m} / \mathrm{s}\right)\left(1 \times 10^{-12} \mathrm{s}\right)=9.1 \times 10^{-7} \mathrm{m}$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 43 - Energy from the Nucleus - Problems - Page 1333: 58b
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