Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 43 - Energy from the Nucleus - Problems - Page 1333: 50e

Answer

$$1.5 \times 10^{10} \mathrm{y} $$

Work Step by Step

The time to lose $0.10 \%$ of its total mass is $$ t=\frac{0.0010 M}{d M / d t}=\frac{|0.0010|\ | 2.0 \times 10^{30} \mathrm{kg} |}{\left|4.3 \times 10^{9} \mathrm{kg} / s\right|\left|3.15 \times 10^{7} \mathrm{s} / \mathrm{y}\right|}=1.5 \times 10^{10} \mathrm{y} $$
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