Answer
$$24.9 \mathrm{\ MeV} $$
Work Step by Step
The energy released is
$$\begin{aligned} Q &=\left(5 m_{2_{ \mathrm{H}}}-m_{{3}_{\mathrm{He}}}-m_{4_ \mathrm{He}}-m_{1_\mathrm{H}}-2 m_{n}\right) c^{2} \\ &=[5(2.014102 \mathrm{u})-3.016029 \mathrm{u}-4.002603 \mathrm{u}-1.007825 \mathrm{u}-2(1.008665 \mathrm{u})](931.5 \mathrm{MeV} / \mathrm{u}) \\ &=24.9 \mathrm{MeV} \end{aligned}$$
