Answer
$
\text { Then, } K_{\mathrm{n}}=Q-K_\alpha \text { yields } 14.05 \mathrm{MeV} \text { for the neutron kinetic energy. }
$
Work Step by Step
$
\text { Then, } K_{\mathrm{n}}=Q-K_\alpha \text { yields } 14.05 \mathrm{MeV} \text { for the neutron kinetic energy. }
$
