## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 84: 11a

#### Answer

$\vec{r}_{(2)} = (6\hat{i} - 106\hat{j})\,m$

#### Work Step by Step

We're given: $\vec{r}_{(2)} = (2t^3-5t)\hat{i} + (6-7t^4)\hat{j}$, where $\vec{r}(t)$ is in meters. We can plug in $t=2\,s$ to obtain: $\vec{r}_{(2)} = ((2*2^3-5*2)\hat{i} + (6-7*2^4)\hat{j})\,m$ $\vec{r}_{(2)} = (6\hat{i} - 106\hat{j})\,m$.

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