Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems: 13a


$8tj + k $

Work Step by Step

The position is given by r = $ i + 4t^2j + tk $ The velocity is the derivative of the position so we need to take $\frac{d}{dt} (i + 4t^2j + tk) $ This gives $0i + 8tj + 1k = 8tj + k $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.