Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1151: 83c

Answer

$p = 6.58~GeV/c$

Work Step by Step

We can find $\gamma$: $\gamma = \frac{1}{\sqrt{1-\beta^2}}$ $\gamma = \frac{1}{\sqrt{1-0.990^2}}$ $\gamma = 7.0888$ We can find the momentum: $p = \gamma mv$ $p = (\gamma)(E_0/c^2) (v)$ $p = (7.0888)(938~MeV/c^2) (0.990~c)$ $p = 6.58~GeV/c$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.