Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1151: 83a

Answer

$K=5.72GeV$

Work Step by Step

To find kinetic energy, the value of gamma must be known. Do this by using a known value of $\beta=0.990$ to get a gamma value of $$\gamma=\frac{1}{\sqrt{1-\beta^2}}=\frac{1}{\sqrt{1-.990^2}}=7.09$$ Substitute this value into the kinetic energy equation $$K=(\gamma-1)mc^2$$ along with $m=1.67 \times 10^{-27}kg$ to get a kinetic energy of $$K=(7.09-1.00)(1.67 \times 10^{-27}kg)(3.00\times 10^8m/s)^2$$ $$K=9.15\times 10^{-10}J$$ Converting joules to GeV yields $$9.15 \times 10^{-10}J \times \frac{1.00GeV}{1.60\times 10^{-10}J}=5.72 GeV$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.