Answer
$t = 3.94\times 10^{-7}~s$
Work Step by Step
In part (a), we found that the length of the spaceship as measured by the timing station is $87.4~m$
We can find the time interval recorded by the timing station:
$t = \frac{d}{v}$
$t = \frac{87.4~m}{(0.740)(3.0\times 10^8~m/s)}$
$t = 3.94\times 10^{-7}~s$
