Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1146: 16c

Answer

The spatial coordinate of the event according to S' is $~~x' = 6.54\times 10^8~m$

Work Step by Step

We can find $\gamma$: $\gamma = \frac{1}{1-\beta^2}$ $\gamma = \frac{1}{1-0.400^2}$ $\gamma = 1.09$ We can find the spatial coordinate $x'$: $x' = \gamma~(x-vt)$ $x' = 1.09~[3.00\times 10^8~m-(-0.400)(3.0\times 10^8~m/s)(2.50~s)]$ $x' = 1.09~[3.00\times 10^8~m+(0.400)(3.0\times 10^8~m/s)(2.50~s)]$ $x' = (1.09)~(6.00\times 10^8~m)$ $x' = 6.54\times 10^8~m$ The spatial coordinate of the event according to S' is $~~x' = 6.54\times 10^8~m$
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