Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1146: 10

Answer

The new length is about 0.63 meters.

Work Step by Step

We can use the length contraction equation using the component of the meter stick parallel to the x-axis. $L_x=L_{x0} \sqrt{1-\beta^2}$ $L_x=1m*\cos30^{\circ} \sqrt{1-(.90)^2}$ $L_x=0.38m$ Now we can use the Pythagorean theorem to find the overall length: $L=\sqrt{L_x^2+ L_y^2}$ $L=\sqrt{(0.38m)^2+ (1m*sin30^{\circ})^2}$ $L \approx 0.63m$
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