Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1146: 18a

Answer

$t' = 0$

Work Step by Step

We can find $\gamma$: $\gamma = \frac{1}{1-\beta^2}$ $\gamma = \frac{1}{1-0.60^2}$ $\gamma = 1.5625$ We can find the temporal coordinate $t'$ of event 1: $t' = \gamma~(t-vx/c^2)$ $t' = 1.5625~[(0)-\frac{(0.60)(3.0\times 10^8~m/s)(0)}{(3.0\times 10^8~m/s)^2}]$ $t' = 0$
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