Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1039: 36b



Work Step by Step

First we consider equation (34-8): $\frac{n_1}{p}+\frac{n_2}{i}=\frac{n_2-n_1}{r}$ Solving for the object distance, $p$, we obtain: $p=n_1(\frac{n_2-n_1}{r}-\frac{n_2}{i})^{-1}$ Using the given values in the table, we have: $p=1.5(\frac{1.0-1.5}{-30cm}-\frac{1.0}{-7.5cm})^{-1}$ $p=+10cm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.