The image distance (i) = +30 cm.
Work Step by Step
The image distance is given by: $1/f = 1/p +1/i$ Solving for i, we obtain: $i = pf/(p-f)$ By substituting p = +60 cm and f = +20 cm, we obtain: $i = (60)(20)/(60-20)\\\\ i = +30 cm$
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