Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1039: 18c

Answer

$r=+16cm$

Work Step by Step

Use the equation relating focal length and radius of curvature $$f=\frac{r}{2}$$ to solve for $r$; $$r=2f$$ We then substitute the known value of $f=+8.0cm$ (see answer 18b for explanation) to get a radius of curvature of $$r=2(+8.0cm)=+16cm$$
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