## Fundamentals of Physics Extended (10th Edition)

$-10cm$
We can use the values from the table in equation 34-3 to find the image distance, $i$: $\frac{1}{p}+\frac{1}{i}=\frac{1}{f}$ Solving for $i$, we have: $i=(\frac{1}{f}-\frac{1}{p})^{-1}$ $i=(\frac{1}{\infty}-\frac{1}{10cm})^{-1}$ $i=-10cm$