Answer
$11\ m$
Work Step by Step
$\vec{w}=\vec{a}-\vec{b}$
$=[4.0m-6.0m]\hat{i}+[-3.0m-8.0m]\hat{j}$
$=(-2.0m)\hat{i}-(11m)\hat{j}$
Using (3-6)
$\vec{a}=a_{x}\hat{\mathrm{i}}+a_{y}\hat{\mathrm{j}} ,$
$a=\sqrt{a_{x}^{2}+a_{y}^{2}}$ and $\displaystyle \tan\theta=\frac{a_{y}}{a_{x}}$ (3-6)
$ w=|\vec{a}-\vec{b}|=\sqrt{(-2.0m)^{2}+(-11m)^{2}}=11\ m\quad$(2 sig.digits)
