Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 3 - Vectors - Problems - Page 58: 30h

Answer

$80^{o}$

Work Step by Step

$\vec{v}=\vec{b}-\vec{a}$ $=[6.0m-4.0m]\hat{i}+[8.0m-(-3.0m)]\hat{j}$ $=(2.0m)\hat{i}+(11m)\hat{j}$ Using (3-6) $\vec{a}=a_{x}\hat{\mathrm{i}}+a_{y}\hat{\mathrm{j}} ,$ $a=\sqrt{a_{x}^{2}+a_{y}^{2}}$ and $\displaystyle \tan\theta=\frac{a_{y}}{a_{x}}$ (3-6) $\displaystyle \theta=\tan^{-1}\frac{11m}{2.0m}=80^{o}\qquad$(2 sig.dig.) (counterclockwise to the +x axis)
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