Answer
$79^{o}$ south of east.
Work Step by Step
Please see solution to part (a).
The second leg of beetle 2, as found in part (a):
$\vec{d}=(0.16 m)\hat{i}+(-0.83m)\hat{j}$
$(b) $
The angle relative to the +x axis (east) is found from
$a=\sqrt{a_{x}^{2}+a_{y}^{2}}$ and $\displaystyle \tan\theta=\frac{a_{y}}{a_{x}}$ (3-6)
$\displaystyle \theta=\tan^{-1}\frac{-0.83}{0.16}=-79^{o},$
or, $79^{o}$ south of east.
