Answer
$32.12\ A$
Work Step by Step
It is given that,
the magnitude of magnetic field $B =7.3 \mu T = 7.3\times 10^{-6}\ T$
Distance from the central axis $R=88\ cm = 0.88\ m$
We know that the current in the wire is $i$.
Therefore, the magnetic field due to a current carrying conductor is:
$B = \frac{\mu_o i}{2\pi R}$
$i=\frac{2\pi RB}{\mu_o}$
$i=\frac{2\pi (0.88\ m)(7.3\times 10^{-6}\ T) }{4\pi\times 10^{-7} H/m}$
$i=32.12\ A$
