Answer
The potential difference for wire B is $~~51.1~V$
Work Step by Step
We can find the equivalent resistance:
$R_{eq} = 0.127~\Omega+0.729~\Omega = 0.856~\Omega$
We can find the current:
$i = \frac{60.0~V}{0.856~\Omega} = 70.09~A$
We can find the potential difference for wire B:
$\Delta V = (70.09~A)(0.729~\Omega) = 51.1~V$
The potential difference for wire B is $~~51.1~V$
