Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 27 - Circuits - Problems - Page 800: 68c

Answer

$V_C = 1000~e^{-t}$

Work Step by Step

We can find an expression for $V_C$: $V_C = \frac{q}{C}$ $V_C = \frac{q_0~e^{-t/RC}}{C}$ $V_C = \frac{(1.0\times 10^{-3}~C)~e^{-t/(1.0\times 10^6~\Omega)(1.0\times 10^{-6}~F)}}{1.0\times 10^{-6}~F}$ $V_C = \frac{(1.0\times 10^{-3}~C)~e^{-t/1}}{1.0\times 10^{-6}~F}$ $V_C = 1000~e^{-t}$
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