Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 27 - Circuits - Problems - Page 800: 73a

Answer

$J = 1.32\times 10^7~A/m^2$

Work Step by Step

We can find the equivalent resistance: $R_{eq} = 0.127~\Omega+0.729~\Omega = 0.856~\Omega$ We can find the current: $i = \frac{60.0~V}{0.856~\Omega} = 70.09~A$ We can find the current density: $J = \frac{current}{area}$ $J = \frac{i}{\pi~r^2}$ $J = \frac{70.09~A}{(\pi)~(1.30\times 10^{-3}~m)^2}$ $J = 1.32\times 10^7~A/m^2$
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