Answer
According to Table 26-1, we can see that wire A is made of copper.
Work Step by Step
We can find the resistivity of the material of wire A:
$R = \frac{\rho~L}{A}$
$\rho = \frac{R~A}{L}$
$\rho = \frac{R~\pi~r^2}{L}$
$\rho = \frac{(0.127~\Omega)(\pi)(1.30\times 10^{-3}~m)^2}{40.0~m}$
$\rho = 1.69\times 10^{-8}~\Omega\cdot m$
According to Table 26-1, we can see that wire A is made of copper.
