Answer
$R' = 88.0~\Omega$
Work Step by Step
The ammeter reading is $~~i = 55.2~mA$
The voltmeter reading is $~~V' = 4.86~V$
We can find $R'$:
$R' = \frac{V'}{i} = \frac{4.86~V}{55.2~mA} = 88.0~\Omega$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 27 - Circuits - Problems - Page 798: 51c
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