Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 27 - Circuits - Problems - Page 796: 25

Answer

$D = 3d$

Work Step by Step

To have the same resistance, the cross-sectional area of the wire with diameter $D$ must have the same cross-sectional area as nine wires of diameter $d$. We can find an expression for $D$: $\pi~(\frac{D}{2})^2 = 9\pi~(\frac{d}{2})^2$ $D^2 = 9d^2$ $D = 3d$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.