Answer
$I=5.56 A$
Work Step by Step
As given that the resistors are connected in parallel so Equivalent Resistance $R_{eq}$ can be calculated as
$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}$
$\frac{1}{R_{eq}}=\frac{1}{18}+\frac{1}{18}+\frac{1}{18}+\frac{1}{18}$
$\frac{1}{R_{eq}}=\frac{4}{18}$
Thus $R_{eq}=\frac{18}{4}=4.5 {\Omega}$
We know that
$V=IR$ or $V=IR_{eq}$
$I=\frac{V}{R_{eq}}$
We plug in the known values to obtain:
$I=\frac{25}{4.5}$
$I=5.56 A$
