Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 27 - Circuits - Problems - Page 796: 22a

Answer

The equivalent resistance is $~~2.50~\Omega$

Work Step by Step

The equivalent resistance of two resistors in series is $2R$ There are three branches in parallel with equivalent resistances (top branch to bottom branch): $2R, R, 2R$ We can find the equivalent resistance: $\frac{1}{R_{eq}} = \frac{1}{2R}+\frac{1}{R}+\frac{1}{2R}$ $\frac{1}{R_{eq}} = \frac{1}{2R}+\frac{2}{2R}+\frac{1}{2R}$ $\frac{1}{R_{eq}} = \frac{4}{2R}$ $R_{eq} = \frac{R}{2}$ $R_{eq} = \frac{5.00~\Omega}{2}$ $R_{eq} = 2.50~\Omega$ The equivalent resistance is $~~2.50~\Omega$
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