Answer
$W_\epsilon=80J$
Work Step by Step
We know that:
$W_\epsilon=Pt$
and $P=i\epsilon$
Thus, we obtain:
$W_\epsilon=i\epsilon t$.....eq(1)
Where $W_\epsilon$ is the energy transferred from chemical form in the battery
We also know that:
$i=\frac{\epsilon}{r+R}=\frac{2}{1+5}=0.33A$
We plug in the known values to obtain:
$W_{e}=(.33A)(2V)(120s)=80J$
