Answer
$\Delta W=11 KJ$
Work Step by Step
We know that electro motive force is given as
$\epsilon=\frac{\Delta W}{\Delta q}$
or $\Delta W=\epsilon\times\Delta Q$.....eq(1)
We also know:
$i=\frac{\Delta q}{\Delta t}$
so $\Delta q=i\Delta t$
substituting values into eq(1)
$\Delta W=\epsilon\times i\Delta t$
We plug in the known values to obtain:
$\Delta W=6\times5 \times (6\times60 sec)$
$\Delta W=10800 J=10.8 KJ$
We round to obtain:
$\Delta W=11 KJ$
