Answer
In the resistor, energy is lost to thermal energy at a rate of $~~23.98~W$
Work Step by Step
In part (a), we found that the current in the circuit is $~~i = 1.99928~A$
We can find the rate at which energy is lost to thermal energy in the resistor:
$P = i^2~R$
$P = (1.99928~A)^2(6.00~\Omega)$
$P = 23.98~W$
.
In the resistor, energy is lost to thermal energy at a rate of $~~23.98~W$
