Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 26 - Current and Resistance - Problems - Page 770: 84a

Answer

$t = 34.9~min$

Work Step by Step

Note that the mass of 2.00 liters of water is 2.00 kg We can find the energy required to raise the temperature of the water: $Q = c~m~\Delta T$ $Q = (4187~J/kg~K)(2.00~kg)(80~K)$ $Q = 669,920~J$ We can find the required time: $t = \frac{E}{P}$ $t = \frac{669,920~J}{(0.80)(400~W)}$ $t = 2093.5~s$ $t = 34.9~min$
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