Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 26 - Current and Resistance - Problems - Page 770: 83

Answer

$t = 113~min$

Work Step by Step

We can write an expression for the original power: $P_0 = \frac{V^2}{R}$ We can write an expression for the new value of the power: $P = \frac{(0.940~V)^2}{R} = 0.8836~P_0$ We can find the new time to provide the required energy $E$: $t = \frac{E}{P}$ $t = \frac{E}{0.8836~P_0}$ $t = 1.1317~\frac{E}{P_0}$ $t = (1.13)~(100~min)$ $t = 113~min$
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