Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 26 - Current and Resistance - Problems - Page 770: 80b

Answer

The percentage change in the area is $~~(2.89\times 10^{-8})~\%$

Work Step by Step

We can find the percentage change in the area: $\frac{(1.70\times 10^{-5})^2~A}{A}\times 100\% = (2.89\times 10^{-8})~\%$ The percentage change in the area is $~~(2.89\times 10^{-8})~\%$
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