Answer
The peak power is $~~2.5\times 10^7~W$
Work Step by Step
We can find the number of electrons per pulse:
$\frac{(0.50~A)(0.10\times 10^{-6}~s)}{1.6\times 10^{-19}~C/electron} = 3.1\times 10^{11}~electrons$
There are $~~3.1\times 10^{11}~electrons~~$ per pulse.
We can find the power when a pulse is generated:
$P = \frac{(3.1\times 10^{11}~electrons)(50\times 10^6~eV/electron)(\frac{1.6\times 10^{-19}~J}{1~eV})}{0.10\times 10^{-6}~s}$
$P = 2.5\times 10^7~W$
The peak power is $~~2.5\times 10^7~W$
