Answer
$J = 3.24\times 10^{-12}~A/m^2$
Work Step by Step
We can find the magnitude of the current density:
$J = \sigma~E$
$J = (2.70\times 10^{-14}~(\Omega\cdot m)^{-1})(120~V/m)$
$J = 3.24\times 10^{-12}~A/m^2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 26 - Current and Resistance - Problems - Page 767: 32a
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