Answer
0.40 ohm
Work Step by Step
We use R Proportional to L/A. The diameter of a 22-gauge wire is 1/4 that of a 10-gauge wire.
Thus from R = p * L/A we find the resistance of 25 ft of 22-gauge copper wire to be
R = (1.00 ohm)(25 ft/1000 ft)*4^{2}
= 0.40 ohm
