Answer
The resistance of the cable is $~~2.12\times 10^{-8}~\Omega$
Work Step by Step
To find the current in each strand, we can divide the total current by the number of strands:
$i = \frac{0.750~A}{125}$
$i = 6.00\times 10^{-3}~A$
$i = 6.00~mA$
We can find the potential difference:
$V = i~R$
$V = (6.00\times 10^{-3}~A)(2.65\times 10^{-6}~\Omega)$
$V = 1.59\times 10^{-8}~V$
The applied potential difference is $~~1.59\times 10^{-8}~V$
We can find the resistance of the cable:
$R = \frac{V}{i}$
$R = \frac{1.59\times 10^{-8}~V}{0.750~A}$
$R = 2.12\times 10^{-8}~\Omega$
The resistance of the cable is $~~2.12\times 10^{-8}~\Omega$
