Answer
$335~nC~~$ of charge passes through a cross-section in $3.00~ms$
Work Step by Step
We can find the current:
$i = \frac{V}{R}$
$i = \frac{V}{\rho~L/A}$
$i = \frac{V~A}{\rho~L}$
$i = \frac{V~\pi~r^2}{\rho~L}$
$i = \frac{(3.00\times 10^{-9}~V)(\pi)(2.00\times 10^{-3}~m)^2}{(1.69\times 10^{-8}~\Omega\cdot m)~(2.00\times 10^{-2}~m)}$
$i = 1.115\times 10^{-4}~A$
We can find the charge that passes through a cross-section in $3.00~ms$:
$q = i~t$
$q = (1.115\times 10^{-4}~A)(3.00\times 10^{-3}~s)$
$q = 3.35\times 10^{-7}~C$
$q = 335~nC$
$335~nC~~$ of charge passes through a cross-section in $3.00~ms$
