Answer
$q=2.5\times10^{-8}C$
Work Step by Step
We know that:
$V=K\frac{q}{r}$
This simplifies to:
$q=\frac{V\times r}{K}$
We plug in the known values to obtain:
$q=\frac{1500\times0.15}{9\times10^9}$
$q=2.5\times10^{-8}C$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 24 - Electric Potential - Problems - Page 714: 65
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