Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 714: 62d

Answer

$\frac{\sigma_1}{\sigma_2} = 2$

Work Step by Step

In part (b), we found that the charge on sphere 1 is $\frac{q}{3}$ In part (c), we found that the charge on sphere 2 is $\frac{2q}{3}$ We can find $\sigma_1$: $\sigma_1 = \frac{q/3}{4\pi R_1^2} = \frac{q}{12\pi R_1^2}$ We can find $\sigma_2$: $\sigma_2 = \frac{2q/3}{4\pi (2.00R_1)^2}$ $\sigma_2 = \frac{2q}{12\pi (4.00R_1^2)}$ $\sigma_2 = \frac{q}{24\pi R_1^2}$ We can find $\frac{\sigma_1}{\sigma_2}$: $\frac{\sigma_1}{\sigma_2} = \frac{\frac{q}{12\pi R_1^2}}{\frac{q}{24\pi R_1^2}}$ $\frac{\sigma_1}{\sigma_2} = \frac{24}{12}$ $\frac{\sigma_1}{\sigma_2} = 2$
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