Answer
$Q=12\mu C$
Work Step by Step
We know that:
$W=\frac{KeQ}{R}$
This can be rearranged as:
$Q=\frac{WR}{Ke}$
We plug in the known values to obtain:
$Q=\frac{2.16\times 10^{-13}\times 0.08}{9\times 10^9(1.6\times 10^{-19})}=12\times 10^{-6}=12\mu C$
