Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 714: 62c

Answer

The fraction of $q$ that ends up on sphere 2 is $~~\frac{2}{3}$

Work Step by Step

$V_1 = \frac{q_1}{4\pi~\epsilon_0~R_1}$ $V_2 = \frac{q_2}{4\pi~\epsilon_0~(2.00R_1)}$ Note that $V_1 = V_2$ and $q_1 = q-q_2$ We can find $q_2$: $V_1 = V_2$ $\frac{q_1}{4\pi~\epsilon_0~R_1} = \frac{q_2}{4\pi~\epsilon_0~(2.00R_1)}$ $2.00~q_1 = q_2$ $2.00~(q-q_2) = q_2$ $3.00~q_2= 2.00q$ $q_2= \frac{2q}{3}$ The fraction of $q$ that ends up on sphere 2 is $~~\frac{2}{3}$.
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