Answer
$E = 0$
Work Step by Step
We can find the magnitude of the electric field at $z = 0$:
$E = \frac{Qz}{4\pi~\epsilon_0~(z^2+R^2)^{3/2}}$
$E = \frac{0}{4\pi~\epsilon_0~(0+R^2)^{3/2}}$
$E = 0$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 22 - Electric Fields - Problems - Page 655: 24a
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