Answer
$F=8.99\times10^9 N$
Work Step by Step
According to Coulomb's law
$F=\frac{q_1q_2}{4\pi{\epsilon_{\circ}}{r^2}}$
but for point charges $q_1=q_2$
thus
$F=\frac{q.q}{4\pi{\epsilon_{\circ}}{r^2}}$
$F=\frac{q^2}{4\pi{\epsilon_{\circ}}{r^2}}$
putting the values, we get
$F=\frac{(1.00)^2}{4(3.14)(8.854\times10^{-12})(1.00)^2}$
$F=8.99\times10^9 N$