Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 21 - Coulomb's Law - Problems - Page 628: 53a

Answer

$F=8.99\times10^9 N$

Work Step by Step

According to Coulomb's law $F=\frac{q_1q_2}{4\pi{\epsilon_{\circ}}{r^2}}$ but for point charges $q_1=q_2$ thus $F=\frac{q.q}{4\pi{\epsilon_{\circ}}{r^2}}$ $F=\frac{q^2}{4\pi{\epsilon_{\circ}}{r^2}}$ putting the values, we get $F=\frac{(1.00)^2}{4(3.14)(8.854\times10^{-12})(1.00)^2}$ $F=8.99\times10^9 N$
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