Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 21 - Coulomb's Law - Problems - Page 628: 45

Answer

$Q = 0.19~MC$

Work Step by Step

One molecule of $H_2$ has two protons. We can find the positive charge in $1.00~mol$ of $H_2$: $Q = (6.02\times 10^{23})(2)(1.6\times 10^{-19}~C)$ $Q = 0.19~MC$
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