Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 21 - Coulomb's Law - Problems - Page 627: 33

Answer

$Q = 1.34\times 10^7~C$

Work Step by Step

$250~cm^3$ of water has a mass of $250~g$ The molar mass of hydrogen is $1.0~g/mol$ The molar mass of oxygen is $16.0~g/mol$ Then the molar mass of a water molecule is $18.0~g/mol$ We can find the number of moles of water: $\frac{250~g}{18.0~g/mol} = 13.89~mol$ We can find the positive charge: $Q = (13.89)(6.02\times 10^{23})(10)(1.6\times 10^{-19}~C)$ $Q = 1.34\times 10^7~C$
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