Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 21 - Coulomb's Law - Problems - Page 627: 31

Answer

$i = 122~mA$

Work Step by Step

We can find the current: $i = (1500e)~(Area)$ $i = (1500e)~(4\pi~r^2)$ $i = (1500)(1.6\times 10^{-19})~(4\pi)~(6.37\times 10^6)^2$ $i = 122\times 10^{-3}~A$ $i = 122~mA$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.